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The perimeter of rectangle ABCD is four times greater than the perimeter of rectangle EFGH.

What is the perimeter of ABCD?

*Perimeter = 2L + 2W*



4x2−x+12

4x2−x+16

8x2−2x+24

16x2−4x+48

16x2−12x+48

4x2−3x+12

The perimeter of rectangle ABCD is four times greater than the perimeter of rectangle-example-1
User Andrea NR
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2 Answers

5 votes

Answer:Find the attached

Explanation:

The perimeter of rectangle ABCD is four times greater than the perimeter of rectangle-example-1
User Nirnroot
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8.3k points
2 votes

Answer:

The answer to your question is 8x² - 2x + 24

Explanation:

Data

EF = x² - x + 6

GF = x² + 1/2x

Perimeter

P = 2L + "W

But the condition is that the perimeter of rectangle ABCD is twice the perimeter of rectangle EFGH so.

Perimeter of EFGH = 4L + 4W

Substitution

Perimeter = 4(x² - x + 6) + 4(x² + 1/2x)

Simplification

Perimeter = 4x² - 4x + 24 + 4x² + 2x

= 8x² - 2x + 24

User Beso
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