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Factor completely 2x4y3 − 12x3y2 − 8x2y.

2x2y(x2y2 − 6xy − 4)
2(x4y3 − 6x3y2 − 4x2y)
2y(x4y2 − 6x3y − 4x2)
Prime

User Ryan Sam
by
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2 Answers

2 votes

Answer:

Question: Factor completely 2x4y3 − 12x3y2 − 8x2y.

Possible Answer: A. 2x2y(x2y2 − 6xy − 4)

User Meenaparam
by
3.1k points
4 votes

Answer:


2x^2y[x^(2)y^(2)-6xy-4]

Explanation:

we have


2x^(4)y^(3)-12x^3y^2-8x^2y

Factor
2x^2y

so


2x^2y[x^(2)y^(2)-6xy-4]

User SYOB SYOT
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