Question

Consider the following code segment for (int n = 2; n < 5; n++) { int k; for (k = n; k > n/2; k--) { System.out.print(""a""); } for (k = n/2; k > 0; k--) { System.out.print(""b""); } System.out.println(); } What is printed as a result of executing the code segment?

Answer 1

The Java code provided uses nested loops to print a series of 'a's followed by 'b's over several lines, changing the count of each letter based on the loop variables. The result is a text output of a decreasing number of 'a's and an increasing number of 'b's for each line.

Step-by-step explanation:

The given code segment is a Java program that uses nested loops to print a sequence of 'a's and 'b's. The outer loop variable n starts at 2 and increments up to 4. For each value of n, the first inner loop decrements k from n to more than n/2, printing an 'a' each iteration. The second inner loop decrements k from n/2 down to 1, printing a 'b' each iteration. Hence, the output will be different patterns of 'a's followed by 'b's for each line based on the current value of n in the outer loop.

The output of this code segment is:

aaabbb
aaabb
aab

Answer 2

The output of the given code as follows:

Output:

ab

aab

aabb

Step-by-step explanation:

The description of the given java code as follows:

In the given code, three for loop is declared, in the first loop, an integer variable n initialized a value, that is 2, and this loop ends, when the value of n is less than 5, this loop prints 3 rows, inside a loop two more for loop is used, that can be described as follows:

• In the second loop, an integer variable k is used, that starts from n value, that is equal to 2, and it will terminate when the value of k is greater than n/2, inside the loop it will print variable "a" as a message.
• In the third loop, it starts with (n/2) and ends with greater than 0, this loop will print the value "b" as a message.
• both the above loop work as a 3D array to print the above pattern.