Question

What mass of Na2SO4 is needed to make 2.0 L of 3.0 M solution (Na = 23 g; S = 32 g; O = 16 g)

Thanks!

Answer 1

710g

Step-by-step explanation:

Answer 2

852g

Step-by-step explanation:

From the question given, we obtained the following information:

Molarity = 3M

Volume = 2L

Mole =?

First, we need to find the number of mole of Na2SO4 present in 2L of the solution. This is achieved by doing the following:

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 3 x 2 = 6moles

Next, we'll find the molar mass of Na2SO4, as illustrated below:

Molar Mass of Na2SO4 = (23x2)+32+(16x4) = 46 + 32 + 64 = 142g/mol

Recall:

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass = 6 x 142 = 852g