Question

A social sciences researcher wants to know about the amount of money that couples without children spend on leisure travel. Her sample of 280 couples yields a mean of $1263.00 and a standard deviation of $160.00. What is the margin of error for a 95% confidence interval?

Answer 1

$18.74

Step-by-step explanation:

the margin of error for a 95% confidence level = Z x (σ / √n)

• Z for a 95% confidence level = 1.96
• standard deviation (σ) = $160
• sample size (n) = 280

the margin of error for a 95% confidence level = 1.96 x ($160 / √280) = 1.96 x ($160 / 16.733) = 1.96 x $9.56 = $18.74