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If a gum-ball machine contains 22 red gum balls, 46 yellow gum balls, 14 green gum balls, and 18 orange gum balls, what is the probability that a gum ball chosen at random will be yellow?
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2 votes
If a gum-ball machine contains 22 red gum balls, 46 yellow gum balls, 14

green gum balls, and 18 orange gum balls, what is the probability that a gum
ball chosen at random will be yellow?

User Gaurang Goda
by
7.7k points

1 Answer

4 votes

Explanation:

22r+46y+14g+18o= 100

46/100= 46%

User Gorbles
by
7.5k points
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