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In the reaction, A -----> Products, the rate constant is 3.6 x 10^−4 s−1. If the initial concentration of A is 0.548 M, what will be the concentration of A (in M) at t = 99.2 s?

Only enter the numerical value with three significant figures in the answer . Do NOT type in the unit (M).

User BaldyHDL
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1 Answer

3 votes

Answer:

0.529

Step-by-step explanation:

Let's consider the reaction A → Products

Since the units of the rate constant are s⁻1, this is a first-order reaction with respect to A.

We can find the concentration of A at a certain time t (
[A]_(t)) using the following expression.


[A]_(t)=[A]_(0).e^(-k* t)

where,

[A]₀: initial concentration of A

k: rate constant


[A]_(t)=0.548M.e^{-3.6* 10^(-4)s^(-1)* 99.2s }


[A]_(t)=0.529 M

User Nigu
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