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Suppose that the eye color and wing shape genes assort independently (they are not linked, i.e., they are located on different chromosomes). In a mating between a female with the genotype w+m+/wm and a male of genotype wm/wm what percentage of the F1 progeny will have a non-parental genotype?A. 100B. 50C. 25D. 75

User Balla
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1 Answer

2 votes

Answer:

50.

Step-by-step explanation:

The independent assortment means the segregation of one pair of trait is not dependent on the other pair of trait. These traits are present on the different chromosome.

The crossing between w+m+/wm female and wm/wm male results in the progeny as w+m/wm (non-parental progeny)-25% ,w+m+/wm (parental progeny)-25%, wm/wm (parental progeny)-25% and wm+/wm(non-parental progeny)-25%. Total 50% progeny are non parental type.

Thus, the correct answer is option (B).

User Ghord
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