Question

Ayyy, wassup people! can y'all do my homework? Imma reward you.

1. Simplify Fully
`(x+3)/(4)+(x-5)/(3)`
2.Write
`(1)/(x+4)+(2)/(x-4)` as a single fraction in it's simplest form.

Answer 1

1) (7x-11)/12

2) (3x+4)/(x²-16)

Explanation:

1)

(x+3)/4 + (x-5)/3

Lcm: 12

[3(x+3) + 4(x-5)]/12

(3x+4x+9-20)/12

(7x-11)/12

2) 1/(x+4) + 2/(x-4)

Lcm: (x+4)(x-4) = x²-16

[(x-4)(1) + (x+4)(2)]/(x²-16)

(x-4+2x+8)/(x²-16)

(3x+4)/(x²-16)

Answer 2

Answer and Step-by-step explanation:

`Good~Day!`

`Let's~answer~your~question~shall~we?`

Answer for the first question:

`=(3(x+3))/(12) +(4(x-5))/(12)`

`=(x(x+3)~+~4(x-5))/(12)`

`=(3x+~9+~4x~4-20)/(12)`

`=(7x~-~11)/(12)`

Answer:

→
`(7x~-~11)/(12)`

________________________________________________

Answer for the second question:

`(x-4)/((x+4)~(x-4)) ~+ ~(2(x+4))/((x+4)~(x-4))`

`=(x-4~+~2~(x+4))/((x+4)~(x-4)) =(x-4~+~2x~+8)/((x+4)~(x-4))`

`=(3x~+~4)/((x+4)~(x-4))`

Answer:

→
`(3x~+~4)/((x+4)~(x-4))`