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A man pushes with a force of 300 N on a bookcase of mass 75 kg. The coefficient of static friction between the bookcase and the floor is 0.9. Because of friction, the bookcase does not move. What is the force of friction on the bookcase?

A. 362 N
B. 300 N
C. 551 N
D. 662 N

User INecas
by
3.2k points

2 Answers

4 votes

Final answer:

The force of friction on the bookcase is 662 N.

Step-by-step explanation:

The force of friction on the bookcase can be found using the equation:

friction force = coefficient of static friction * normal force

The normal force is equal to the weight of the bookcase, which can be found using the equation:

weight = mass * gravity

Substituting the given values:

weight = 75 kg * 9.8 m/s^2

The coefficient of static friction is 0.9, so the force of friction can be calculated as:

friction force = 0.9 * weight

Substituting the weight value:

friction force = 0.9 * (75 kg * 9.8 m/s^2)

Solving this equation gives an answer of 662 N.

User Hustlion
by
3.3k points
4 votes

Answer: 300 N

Step-by-step explanation:

The friction acting on a static object is equal to the force put on it.

User Yatul
by
3.2k points