Which equation has the solutions x = 1+ V5? A) x^2 + 2х + 4 = 0 B) x^2 — 2х + 4 = 0 C) х^2 + 2х – 4 = 0 D) x^2— 2х

asked May 8, 2021 149k views

5 votes

Which equation has the solutions x = 1+ V5?

A) x^2 + 2х + 4 = 0
B) x^2 — 2х + 4 = 0
C) х^2 + 2х – 4 = 0
D) x^2— 2х – 4 = 0

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3 votes

Answer:

x^2-2x-4=0

Δ=2^2-4*1*(-4)

Δ=4+16=20

VΔ=2V5

x1= (2+2V5)/2=1+V5

the answer is D

Explanation:

Matti Lehtinen answered May 12, 2021

3.4k points

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