Answer:
NO
Step-by-step explanation:
The angular position of a diffraction null is given by
Asinθ=m λ=m c/f
Given that A is the slit width,
and m is an integer.
The wavelength of the second null satisfies
λ= A sinθ₁/2
of which if there were distinct third null it will satisfy
sinθ₂=3λ/A= 3* sin 45/2
λ=(3*0.7071)/2
λ=2.121/2
λ=1.060
Of which 1.060 is greater than 1