Write 3 fractions, using 10 as the denominator, who's sum is 1
![(1)/(10), (3)/(10), (6)/(10)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ec3o5jkk5u5nd50djuenlrijdmyuynnkyb.png)
Solution:
Given that,
We have to write 3 fractions, using 10 as the denominator, who's sum is 1
We know that, fraction is written as:
![fraction = (numerator)/(denominator)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/f3rt4rln14yz18s8qz2t2279ti9xnlk8rn.png)
We have to write 3 fractions with 10 as denominator
![(1)/(10)\\\\(3)/(10)\\\\(6)/(10)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/u4iqbp08ekg42yzecffmoyxjrt6zr82q1m.png)
Add these to check if its sum is 1
![sum = (1)/(10) + (3)/(10) + (6)/(10)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/l26u7trqejwi45fvwmjncetz4sqgry28gd.png)
When denominators are same, we can add the numerators
![sum = (1+3+6)/(10)\\\\sum = (10)/(10)\\\\sum = 1](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5eyjydflk8iln1ugjizch66k8ys79cbba1.png)
Thus the three fractions are:
![(1)/(10), (3)/(10), (6)/(10)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ec3o5jkk5u5nd50djuenlrijdmyuynnkyb.png)