Question

The barrier to rotation of bromoethane is 15 kJ/mol. Based on this information, determine the energy cost associated with the eclipsing interaction between a bromine atom and a hydrogen atom.

Answer 1

Answer is 7KJ

Step-by-step explanation:

H and H eclipsed confirmation = 4 KJ

There are two H and H eclipsed ones = 2*4 = 8 KJ

Energy of H and Br eclisped interaction = Energy rotation - 2*Energy of H and H eclipsed = 15 -2*4 = 7 KJ