Answer:
Maximum flow rate is 1290L/min
Step-by-step explanation:
Mass rate of accumulation = mass rate of input – mass rate of output
350m^3 (1000L/m^3) = (x)(6hours)(60min/hour) - (320L/min)(6hours)(60min/hour)
3.5 × 10^3L + 4.65 × 10^3L = x(360min)
X = 1290L/min.