Question

Consider functions f and g

Answer 1

A

Explanation:

`f(x) = (x - 16)/(x^2 + 6x - 40)`

`g(x) = (1)/(x + 10)`

`f(x) + g(x) =  (x - 16)/(x^2 + 6x - 40) + (1)/(x + 10)`

`f(x) + g(x) =  (x - 16)/(x^2 + 6x - 40) + ((x - 4))/((x + 10)(x - 4))`

`f(x) + g(x) =  (x - 16 + x - 4)/(x^2 + 6x - 40)`

`f(x) + g(x) =  (2x - 20)/(x^2 + 6x - 40)`

Answer: A