Question

6. Aaron will run from home at y mph and walk back at x mph. how much distance does he need to travel to spend a total of t hours walking and jogging. (A) xt/y (B) (x+t)/xy (C) xyt/(x+y) (D) (x+y+t)/xy (E) (y+t)/x-t/y

Answer 1

Total distance,
`d=(xyt)/((x+y))`

Step-by-step explanation:

It is given that,

Speed of Aaron from home is y mph and walk back at x mph. Let t is the total time he spend in walking and jogging. Let d is the distance covered.

We he moves from home to destination, time is equal to,
`(d)/(x)`

Similarly, when he move back to home, time taken is equal to
`(d)/(y)`

Total time taken is equal to :

`(d)/(x)+(d)/(y)=t`

`d((1)/(x)+(1)/(y))=t`

`d=(t)/(((1)/(x)+(1)/(y)))`

`d=(xyt)/((x+y))`

So, the distance he speed in walking and jogging is
`(xyt)/((x+y))`. Hence, this is the required solution.