Question

Two loudspeakers emit 600 Hz Hz notes. One speaker sits on the ground. The other speaker is in the back of a pickup truck. You hear 7.00 beats per second as the truck drives away from you. What is the truck'sspeed?

Answer 1

The truck's speed is 4.04 m/s.

Step-by-step explanation:

Given that,

Emit frequency = 600 Hz

Beat = 7.00 beat/sec

We need to calculate the truck's speed

Using formula of speed

`\text{frequency observed}=\text{frequency emitted}*(v)/(v+v_(source))`

Where, v = speed of sound

Put the value into the formula

`(600-7)=600*((343)/(343-v_(truck)))`

`v_(truck)=(600*343-593*343)/(593)`

`v_(truck)=4.04\ m/s`

Hence, The truck's speed is 4.04 m/s.