Question

The electric field just above the surface of the charged drum of a photocopying machine has a magnitude E of 2.3 ✕ 105 N/C. The drum has a length of 55 cm and a diameter of 11 cm. What is the total charge on the drum?

Answer 1

`1.68* 10^(-7) C`

Step-by-step explanation:

Electric field=
`E=2.3* 1065 N/C`

Length of drum=l=55 cm=
`(55)/(100)=0.55 m`

Using 1 m=100 cm

Diameter ,d=11 cm=
`(11)/(100)=0.11 m`

We have to find the total charge on the drum.

We know that

`q=\sigma A=\pi\epsilon_0Edl`

`\epsilon_0=8.85* 10^(-12) C^2/Nm^2`

`\pi=3.14`

Substitute the values

`q=3.14* 8.85* 10^(-12)* 2.3* 10^5* 0.55* 0.11}`

`q=1.68* 10^(-7) C`