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Two parallel surfaces move relative to each other are separated by a gap of 0.375 in. The gap is filled by a fluid of with .00431 lb-sec/in2 viscosity. The relative motion is resisted by a shear stress of 0.25 lb/in2 due to the viscosity of the fluid. What is the velocity of the parallel surfaces above assuming the velocity gradient in the space between the surfaces is constant?

User TimeEmit
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Answer:

Velocity will be 21.75in/sec

Diagram well explains the calculation.

Two parallel surfaces move relative to each other are separated by a gap of 0.375 in-example-1
User Nllsdfx
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