Answer:
the probability that exactly 1 received a special accommodation is 0.3079
Explanation:
Step 1: define the variable
x= the number of students who received a special accommodation.
Step 2: define the distribution of this variable
x ~ binomial distribution ( p=0.02, n=25)
this is because x is the number of succes in 25 trials.
Step 3: using the binomial distribution formula
P(x=1)= (25C1)*(0.05^1)*(1-0.05)^(25-1)=0.3079
where (25C1) is a combination