Question

A beaker contains 100.0 mL of a 0.100 M solution of sulfuric acid. When 100.0 mL water is added to this solution, what is the concentration of the diluted sulfuric acid?

Answer 1

0.05 M.

Step-by-step explanation:

For the concentrated sulphuric acid,

Number of moles = molar concentration × volume

= 0.1 × 0.1

= 0.01 mol

New volume = 100 + 100 ml

= 200 ml

Concentration of the diluted sulphuric acid = number of moles/volume

= 0.01/0.200

= 0.05 M