Question

A Carnot engine operates between reservoirs at 600 and 300 K. If the engine absorbs 100 J per cycle at the hot reservoir, what is its work output per cycle?

Answer 1

W =50 J

Step-by-step explanation:

given data:

T_h=600 k

T_L=300 k

Q_h=100 J

required:

W=??

solution:

║W║=║Q_h║(1-T_L/T_h)

=50 J

Answer 2

50J

Step-by-step explanation:

For a Carnot engine, the work output (W) per cycle is given by;

W = Q (1 -
`(T_(C) )/(T_(H))`) ----------------(i)

Where;

Q = heat absorbed by the engine per cycle

`T_(C)` = Temperature of the colder reservoir

`T_(H)` = Temperature of the hotter reservoir

From the question;

Q = 100J

`T_(C)` = 300K

`T_(H)` = 600K

Substitute these values into equation (i) as follows;

W = 100 (1 -
`(300 )/(600)`)

W = 100 (1 -
`(1)/(2)`)

W = 100 (
`(1)/(2)`)

W = 50 J

Therefore, the work output per cycle is 50J