Question

An object traveling along the x-axis at constant acceleration has a velocity of +10m/s when it is at x=6.0 m and of +15m/s when it is at x=10.0m. What is its acceleration?

Answer 1

`15.625m/s^2`

Step-by-step explanation:

We us the third equation of a uniformly accelerated motion.

`v^2=u^2+2as.................(1)`

where v is the final velocity, u the initial velocity, a the acceleration and s the distance covered.

Given;

v = 15m/s

u = 10m/s

the distance covered is given by;

`s=x_2-x_1...............(2)`

where,

`x_2=10.0m\\x_1=6.0m`

Therefore,

`s=10.0-6.0\\s=4.0m`

Substituting all values into equation (1);

`15^2=10^2+2*a*4\\225=100+8a\\8a=225-100\\8a=125\\a=(125)/(8)\\a=15.625m/s^2`