Question

At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats facing the axis, their backs against the outer wall. At one instant the outer wall moves at a speed of 2.72 m/s, and an 75.1-kg person feels a 235-N force pressing against his back. What is the radius of a chamber?

Answer 1

The radius of a chamber is 2.36 meters.

Step-by-step explanation:

Given that,

The outer wall moves at a speed of 2.72 m/s.

Mass of the person, m = 75.1 kg

The person feels a force of 235 N force pressing against his back. The force acting on the person is centripetal force. It is given by the below formula :

`F=(mv^2)/(r)`

r is the radius of a chamber

`r=(mv^2)/(F)`

`r=(75.1* (2.72)^2)/(235)`

r = 2.36 meters

So, the radius of a chamber is 2.36 meters. Hence, this is the required solution.