Answer:
a) the probability that the ball selected is new is 0.475
b) the probability the ball is from the first bucket is 0.2381
Explanation:
A = the ball selected is new
B = the bucket selected by the coach is de first one.
P(A|B) = 15/(15+5)=0.75
P(A|B') = 2/(2+8)=0.2
P(B) = 0.5
a) by the total probability theorem
P(A) = P(A∩B) +P(A∩B') = P(A|B)*P(B) + P(A|B')*P(B') = 0.75*0.5+0.2*(1-0.5)=0.475
b) by the bayes rule
P(B|A')=P(A'|B)P(B)/P(A') = (1-0.75)*0.5/(1-0.475)=0.2381