Question

A simple pendulum consists of a 2 kg bob attached to a 1.5 m long string. How much time (in s) is required for this pendulum to complete 2.5 oscillations?

Answer 1

6.15 s

Step-by-step explanation:

The period of a simple pendulum is given by the equation

`T=2\pi \sqrt{(L)/(g)}`

where

L is the length of the pendulum

g is the acceleration of gravity

For the pendulum in this problem,

L = 1.5 m (length)

`g=9.8 m/s^2` (acceleration due to gravity on Earth)

Therefore, its period is

`T=2\pi \sqrt{(1.5)/(9.8)}=2.46 s`

And therefore, the time taken for the pendulum to complete 2.5 oscillations is equal to 2.5 times the period:

`t=2.5T=(2.5)(2.46)=6.15 s`