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For an exam with a mean of M = 74 and a standard deviation of s = 8, Mary has a score of X = 80, Bob’s score corresponds to z = +1.50, and Sue’s score is located above the mean by 10 points. If the students are placed in order from smallest score to largest score, what is the correct order?​

User Pwaring
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1 Answer

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Given Information:

Mean = μ = 74

Standard deviation = σ = 8

Mary's score = x = 80

Bob’s score = z = +1.50

Sue’s score = above the mean by 10 points

Required Information:

If the students are placed in order from smallest score to largest score, what is the correct order?

Answer:

Mary = 80, Sue = 84, Bob = 86

Step-by-step explanation:

Bob's score:

z = (x - μ)/σ

x - μ = zσ

x = zσ + μ

x = 1.50*8 + 74

x = 12 + 74

x = 86

Sue's score:

x = u + 10

x = 74 + 10

x = 84

Mary's score:

x = 80

From the smallest score to largest score

Mary = 80, Sue = 84, Bob = 86

User Jordancpaul
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