Question

What is the axis of symmetry for y=2x^2+16x-5

Answer 1

x=-4

Explanation:

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Answer 2

`x=-4`

Explanation:

Convert to vertex form by completing the square

`y=2x^2+16x-5\\\\y=2(x^2+8x-(5)/(2))\\ \\y+2((37)/(2))=2(x^2+8x-(5)/(2)+(37)/(2))\\ \\y+37=2(x^2+8x+16)\\\\y+37=2(x+4)^2\\\\y=2(x+4)^2-37`

Since the equation is now in the form of
`y=a(x-h)^2+k`, the axis of symmetry is where
`x=h`, so, the axis of symmetry is
`x=-4`.