Question

What number pattern is generated by the following

equation when n = 1, 2, 3, 4, ...? 3n + n/4 + 1

Answer 1

nth term = 1 + n(13/4)

Explanation:

3n + n/4 + 1

n = 1, 3(1) + (1)/4 + 1 = 4 + ¼ = 17/4

n = 2, 3(2) + (2)/4 + 1 = 7 + ½ = 30/4

n = 3, 3(3) + (3)/4 + 1 = 10 + ¾ = 43/4

n = 4, 3(4) + (4)/4 + 1 = 14 = 56/4

The difference between consecutive terms is 13/4

At n = 1, 17/4 = 1 + 1(13/4)

At n = 2, 30/4 = 1 + 2(13/4)

nth term = 1 + n(13/4)