Answer:
![336 m^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5wl4zs4sywmqhqkyv8tpzc9wxpt5v867i0.png)
Explanation:
The surface area of a square pyramid is the sum of the area of the squared base + 4 times the area of each triangular face, therefore:
![A=A_b + 4A_t](https://img.qammunity.org/2021/formulas/mathematics/middle-school/81rjarwfstbgxb4tfpq36r9gtumgfvlqh6.png)
where:
is the area of the base, where
L is the length of the base
is the area of each triangular face, where
h is the height of the face
Substituting,
![A=L^2+2Lh](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vuwq9y450l8ghfn7kjrtyh6d18rqpphgbg.png)
For the model in this problem,
L = 12
h = 8
Therefore, the surface area here is:
![A=12^2 +2(12)(8)=336](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ge5pc4ovdkb7oj4wkt1tbch32d04ki0r5z.png)