Answer:
![(2)/(7)](https://img.qammunity.org/2021/formulas/mathematics/college/whmts5ovrqa5jpj8t5j7w86tgbzyeuo6b8.png)
Explanation:
Given:
A car starts with a dull tank of gas
1/7 of the gas has been used around the city.
With the rest of the gas in the car, the car can travel to and from Ottawa three times.
Question asked:
What fractions of a tank of gas does each complete trip to Ottawa use?
Solution:
Fuel used around the city =
![(1)/(7)](https://img.qammunity.org/2021/formulas/business/high-school/z5vgv1aqqr5lifasatuxhsh0u39ldrrnoe.png)
Remaining fuel after driving around the city = 1 -
=
![(7 - 1)/(7) = (6)/(7)](https://img.qammunity.org/2021/formulas/mathematics/high-school/jvnuh8ydkwspwwvdyx9hy6shy9reg637qn.png)
According to question:
As from the rest of the gas in the car that is
, the car can complete 3 trip to Ottawa which means,
By unitary method:
The car can complete 3 trip by using =
tank of gas.
The car can complete 1 trip by using =
![(6)/(7) / 3](https://img.qammunity.org/2021/formulas/mathematics/high-school/jqqkhf5xjr2a9ne3pe9huf5eflpctlj1j3.png)
=
![(6)/(7) *(1)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/mbml63tiymofrznw8ra8cx4rxe60r94r2y.png)
=
![(6)/(21)](https://img.qammunity.org/2021/formulas/mathematics/high-school/4z9w0z3j8vobtp2pzjwrsrcfa4e8nf064y.png)
=
tank of gas
Thus,
tank of gas used for each complete trip to Ottawa.