Answer:
Step-by-step explanation:
83.0g excess ? mol
2Na + Cl2X = 2 NaCl
2 mol 1 mol 2 mol
23g/mol
83g x 1 mol/23g = 3.61 mol Na
3.61 mol Na X 2 mol NaCl/2 Mol Na =3.6 mol NaCl
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