Question

A subsurface exploration report shows that the average water content of a fine-grained soil in a proposed borrow area is 22% and that its average natural dry density is 82 pcf. This soil is to be placed in a compacted fill with a dry density specified at 96 pcf. How many cubic yards of borrow will be required to produce 50,000 yd3 of fill? What is the shrinkage factor for the borrow?

Answer 1

shrinkage ratio = 1.538

Step-by-step explanation:

given data

water content = 22 %

dry density γ = 82 pcf

required dry density specified γ' = 96 pcf

required to produce = 50,000 yd³ = 50000 × 27 = 1350,000 ft³

solution

we get here first volume of borrow pit that is we know that

dry density ∝
`(1)/(volume)`

so
`(\gamma d)/(\gamma 'd) = (v')/(v)`

`(82)/(96) = (1350000)/(v)`

v = 1580487.8 ft³

v = 58536.58 yd³

so here

shrinkage ratio will be as

shrinkage ratio =
`(96)/(62.4)`

shrinkage ratio = 1.538