Question

3. A clown rides a small car at a speed of

15 km/h along a circular path with a
radius of 3.5 m. What is the
magnitude of the centripetal force on a
0.18-kg ball held by the clown?​

Answer 1

0.89 N

Step-by-step explanation:

Centripetal force is mass time centripetal acceleration.

F = ma

F = m v² / r

Given m = 0.18 kg, v = 15 km/h = 4.17 m/s, and r = 3.5 m:

F = (0.18 kg) (4.17 m/s)² / (3.5 m)

F = 0.89 N