Question

How would i solve this correctly?

Answer 1

x = 26

Explanation:

`√(2x-3)=7\qquad\text{given}\\\\2x-3=7^2\qquad\text{square both sides}\\\\2x=52\qquad\text{add 3}\\\\x=26\qquad\text{divide by 2}`

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In general, you undo what is done to the variable. Here, the variable is ...

• multiplied by 2
• 3 subtracted from the product
• square root of the difference

You undo these operations in reverse order. To undo the square root, you square both sides of the equation. To undo the subtraction, you add 3. To undo the multiplication, you multiply by the reciprocal of 2 (equivalently, divide by 2).

Whatever you do to one side of the equation must also be done to the other side of the equation. That is how the equal sign stays valid.