Question

What is the equation for the circle with center (-9, 5) and radius 4

Answer 1

• (h,k)=(-9,5)
• r=4

Equation:-

• (x-h)²+(y-k)²=r^2
• (x-(-9))2+(y-5)^2=4^2
• (x+9)^2+(y-5)^2=16
• x^2+18x+81+y^2-10x+25=16[/tex]
• 
  `\\ \rm\rightarrowtail x^2+y^2+8x+90=0`

Answer 2

`\sf (x+9)^2+(y-5)^2=16`

Explanation:

Standard equation of a circle:
`\sf (x-h)^2+(y-k)^2=r^2`

(where (h, k) is the center of the circle and r is the radius)

Given:

• center = (-9, 5)
• radius = 4

Substituting given values into the equation:

`\sf \implies (x-(-9))^2+(y-5)^2=4^2`

`\sf \implies (x+9)^2+(y-5)^2=16`