Question

What is the center and radius of the circle?
(x-3)2 + y² = 4

Answer 1

center = (3, 0)

radius = 2

Explanation:

Standard equation of a circle:
`\sf (x-h)^2+(y-k)^2=r^2`

(where (h, k) is the center of the circle and r is the radius)

Given equation:

`\sf (x-3)^2+y^2=4`

Rewrite in standard form:

`\sf \implies (x-3)^2+(y-0)^2=2^2`

Therefore

• center = (3, 0)
• radius = 2