Question

Determine the temperature (in K) of 0.6 moles of gas contained in a 1.7 L vessels at a pressure of 154.2 kPa.

Answer 1

51.6K

Step-by-step explanation:

Given parameters:

number of moles = 0.6moles

Volume = 1.7L

Pressure = 154.2kPa

Unknown:

temperature = ?

Solution

The ideal gas law is best used to solve this kind of problem. The law combines Boyle's law, Charles's law and Avogadro's law.

PV = nRT

wherre P = pressure in atm

V = volume in dm³ or L

n = number of moles

R = gas constant

T = temperature in kelvin

Since T is the unknown, we make it the subject of the expression;

T =
`(PV)/(nR)`

1atm = 101325Pa

x atm = 154.2 x 10³Pa

x =
`(154200)/(101325)` = 1.52atm

T =
`(1.52 x 1.7)/(0.6 x 0.082)` =
`(2.58)/(0.05)` = 51.6K