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3 votes
Problem situation:

Anna is at the movie theater and has $35 to spend.
She spends $9.50 on a ticket and wants to buy some snacks. Each snack costs $3.50.
How many snacks, , can Anna buy?

Inequality that represents this situation:
9.50+3.50≤35

Drag each number to show if it is a solution to both the inequality and the problem situation, to the inequality only, or if it is not a solution.

Problem situation: Anna is at the movie theater and has $35 to spend. She spends $9.50 on-example-1

2 Answers

3 votes

Answer:

these are the answers ;)

solution to both: 2,4

solution to inequality ONLY: -2,4.25,3 1/4

NOT a solution: 9 1/2

Explanation:

I plugged the variables for each one and found the answers

User Noha Kareem
by
4.2k points
0 votes

Answer:

  • solution to both: 2, 4
  • solution to inequality only: -2, 4.25, 3 1/4
  • not a solution: 9 1/2

Explanation:

Using x for the variable, the inequality will be ...

9.50 +3.50x ≤ 35

3.50x ≤ 25.50

x ≤ 51/7 ≈ 7.3

Anna cannot buy negative snacks, and she cannot buy fractional snacks. Of the numbers listed, only 2 and 4 are integers between 0 and 7 (inclusive). The values below 7.3 are all solutions to the inequality. The value 9 1/2 is too large to be a solution to the inequality.

Only 2 and 4 are solutions to both the problem and the inequality.

9 1/2 is not a solution.

User Nazark
by
4.6k points