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3 votes
How do you simplify
7\sqrt[4]{80pq^(2)r^(8) }?

User Ralf H
by
3.7k points

1 Answer

5 votes

Answer:


14 ( 5)^{(1)/(4)} p^{(1)/(4)} q^{(1)/(2)} r^(2)

Explanation:

The expression to simplify in this problem is


7\sqrt[4]{80pq^2r^8}

Which can be rewritten as


7(80pq^2r^8)^{(1)/(4)}

Or also as


7\cdot 80^{(1)/(4)} \cdot p^{(1)/(4)} \cdot (q^2)^{(1)/(4)} \cdot (r^8)^{(1)/(4)}

Now we can apply the following rule for the calculation of the power of a power:


(a^m)^n = a^(m\cdot n)

So we get:


7\cdot 80^{(1)/(4)} \cdot p^{(1)/(4)} \cdot q^{(1)/(2)} \cdot r^(2)

Which can therefore be rewritten as


7\cdot (2^4\cdot 5)^{(1)/(4)} \cdot p^{(1)/(4)} \cdot q^{(1)/(2)} \cdot r^(2)

And so, we get


7\cdot 2 \cdot ( 5)^{(1)/(4)} \cdot p^{(1)/(4)} \cdot q^{(1)/(2)} \cdot r^(2)

which can be finally rewritten as


14 ( 5)^{(1)/(4)} p^{(1)/(4)} q^{(1)/(2)} r^(2)

User Khylo
by
3.8k points