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A survey for brand recognition is done and it is determined that 68% of consumers have heard of Dull Computer Company. A survey of 800 randomly selected consumers is to be conducted. For such groups of 800, would it be unusual get 556 consumers who recognize the Dull Computer Company name?

User Maxspan
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Answer:

No, it would be usual

Explanation:

The mean will be
\frac {68}{100}* 800=544

Standard deviation
s=\sqrt {np(1-p)}=\sqrt {800*0.68*(1-0.68)}=13.2

The confidence level will be mean±2*standard deviation

Confidence level= 544±2*13.2=544±26.6 hence 517.6 or 570.4

Getting 556 consumers who recognize the Dull Computer Company name won't be unusual because it's within limits

User Sushildlh
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