Question

Question 20: Please help what are sin x and cos x?

Answer 1

A is the correct answer.

Explanation:

`\tan x = (6)/(8) = (opposite \: side \: to \: \angle \: x)/(adjacent \: side \: to \: \angle \: x) \\ \\ hypotenuse \\ = \sqrt{ {(opp. \: side)}^(2) + {(adj. \: side)}^(2) } \\ = \sqrt{ {6}^(2) + {8}^(2) } \\ = √(36 + 64) \\ = √(100) \\ = 10 \\ \\ \because \sin (x) = (opposite \: side \: to \: \angle \: x)/(hypotenuse) \\ \\ \huge{ \red{ \boxed{\therefore \: \sin (x) = (6)/(10)}}} \\ \\ \cos (x) = (adjacent \: side \: to \: \angle \: x)/(hypotenuse) \\ \\ \huge{ \purple{ \boxed{\therefore \: \cos (x) = (8)/(10) }}} \\`

Thus, option A is the correct answer.