Answer:
a) 4
b) 5
c) 9
Explanation:
a) let the 12th number b x
Mean = sum/n
5.5 = (5+6+5+3+4+5+7+6+9+7+5+x)/12
5.5×12 = 62+x
66 = 62+x
x = 4
b) set is: 3,4,4,5,5,5,5,6,6,7,7,9
Mode is 5 (most frequent)
c) mode+mean = 5+4 = 9
A) 4
B) Mode is 5
C) 10.5
A) 62+x/12
(62 + x) ÷ 12 = 5.5 ×12
62 + x = 66
×= 66-62
×=4
B) mode is the highest occuring no which is 5
C) mean has been given as 5.5; mean plus mode= 10.5
3.5m questions
4.5m answers