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Given: KLMN is a parallelogram, KA − angle bisector of ∠K LA − angle bisector of ∠L Prove: m∠KAL = 90°
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Given: KLMN is a parallelogram, KA − angle bisector of ∠K LA − angle bisector of ∠L Prove: m∠KAL = 90°

User Ramon Bakker
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Answer: angle KAL = 90°

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Given: KLMN is a parallelogram, KA − angle bisector of ∠K LA − angle bisector of ∠L-example-1
User Mark Rabjohn
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