Question

Calculate the energy (in Mev’s) released in the reaction:2/1H+3/1H—4/2He+1/on+E

Answer 1

`\large \boxed{\text{17.59 MeV}}`

Step-by-step explanation:

`\rm _(1)^(2)\text{H} + \, _(1)^(3)\text{H} \longrightarrow \, _(2)^(4)\text{He} + \,_(0)^(1)\text{n} + E`

1. Calculate the mass difference

Mass of ₁²H = 2.014 102 u

Mass of ₁³H = 3.016 049

Total = 5.030 151 u

Mass of ₂⁴He = 4.002 603

Mass of ₀¹n = 1.008 665

Total = 5.011 268

Difference = 0.018 883 u

2. Convert the mass difference to energy.

931.5 MeV = 1 u

`\text{Energy} = \text{0.018 883 u} * \frac{\text{931.5 MeV}}{\text{1 u}} = \textbf{17.59 MeV}\\\\\text{The energy released is $\large \boxed{\textbf{17.59 MeV}}$}`