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Sodium hydroxide (0.400 mol) is allowed to react with an excess of sulfuric acid. How many moles of sodium sulfate could be recovered from the products? NaOH + H2SO4 → Na2SO4 + H20
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Sodium hydroxide (0.400 mol) is allowed to react with an excess of sulfuric acid. How many moles of

sodium sulfate could be recovered from the products?

NaOH + H2SO4 → Na2SO4 + H20

User Gustav Larsson
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1 Answer

12 votes

Answer:

2 moles

Step-by-step explanation:

In this reaction, the stoichiometry (mole ratio) is 1 mole of sulfuric acid reacting with 2 moles of sodium hydroxide (1:2 ratio)

User Marpme
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