Question

PLEASE HELP ME.....

Erik took a trip to see his friend Mike who lives 308 miles away. He left his place at 10 AM driving at 70 mph. In 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph. At what time will they meet?

Answer 1

They would meet each other at
`01 : 24` PM.

Explanation:

• Erik took a trip to see his friend Mike who lives 308 miles away.

• He left his place at 10 AM driving at 70 mph.

• In 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph.

As Erik left his house at 10 AM driving at 70 mph and in 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph. It means

Erik left his place at 12:00 PM noon.

so, at 12:00 PM Erik had already traveled:

`2* 70=140\:\:miles`

Miles left
`=308-140=168\:\:miles`

Let 't' be the time when they meet

so

`70t\:+\:50t\:=168`

`120t=168`

`\mathrm{Divide\:both\:sides\:by\:}120`

`(120t)/(120)=(168)/(120)`

`t=(7)/(5)`

so

`t=(7)/(5)=1.4\:\:hours`

or
`1` hour and
`24` minutes after
`12:00` noon

i.e.

`12\:+\:1.4\:=1\:O'clock\:+\:24\:minutes`

Therefore, they would meet each other at
`01 : 24` PM.