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An object of mass 0.5 kg is swung in uniform circular motion. The radius is 2 meters, and the force exerted is 4 N. Calculate the centripetal acceleration.

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Answer:

8 m/s²

Step-by-step explanation:

m = 0.5kg

r = 2m

F = 4 N


f= \frac{ {mv}^(2) }{r}

make v the subject


v = \sqrt{( (fr)/(m)) }

v = √(4×2)/0.5

v = √16

v = 4 m/s


a = \frac{ {v}^(2) }{r}

a = 4²/2

a = 16/2

a = 8 m/s²

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