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PLEASE HELP!!!!!!!!!

PLEASE HELP!!!!!!!!!-example-1

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Answer:

114

Explanation:

The external angle measure is equal to the half of difference between the larger intercepted arc (5x-12) and the smaller intercepted arc (3x)

32 = (5x-12 -3x)/2

combine like terms in parenthesis and multiply both sides by 2

32·2 = 2x-12

multiply 32·2 = 64, and add 12 to both sides

64 + 12 = 2x

add 64+12 = 76, and divide both sides by 2 to isolate x

76/2 = x

38 = x

The measure of arc AB is 3x.

Substitute x for 38

Measure of arc AB = 3x = 3·38 = 114

User Romylussone
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